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mcqs of chemistry class 11 chapter 3

Question 33. (d) 10. Describe the theory associated with the radius of an atom as it: Which element do you think would have been named by Students who can Practice CBSE Class 11 Chemistry Multiple Choice Questions with Answers to improve your score in Board Exams. Electronic configuration.=1s2 2s2 2p6 3s2 3p6 3d2 4s2, and the element name is Titanium (Ti). Answer: The elements in a group have same valence shell electronic configuration and hence have similar physical and chemical properties. In some cases, like in noble gas, atoms do not have any attraction to gain an electron. NCERT Solutions for Class 6, 7, 8, 9, 10, 11 and 12. On moving down the group there is an increase in the principal quantum number and therefore no. Predict the formulas of the stable binary compounds that would be formed by the combination of the following pairs of elements: Make use of the Chapter Wise MCQ Quiz Questions for Class 12 Chemistry to get a good grip on the concepts. Atomic Radii. Answer: Horizontal rows are called periods and vertical columns are called groups. Thus element belong to 3rd period, p-block element. Answer: Al and Si. Complete electronic configuration =[Xe] 4 f7 5d1 6s2. (a) halogens (b) alkaline earth metals electrons. For example. Free Online MCQs Questions for Class 11 Business Studies with Answers was Prepared Based on Latest Exam Pattern. (e) The element VI has low first ionization enthalpy (∆ iH1) but higher than that of alkali metals. Answer: Ionization enthalpy, among other things, depends upon the electronic configuration (number of electrons) and nuclear charge (number of protons). Download Multiple Choice Questions of Class 12 Chemistry. Question 6. Justified positions are provided to transition and inner transition elements. (ii)K+  (iv) Sr2+, Question 12. Chapter 2 - Structure of Atom 23 videos | 16 docs | 15 tests Wave Nature of Electromagnetic … O8 =1s2 2s2 2px1 2py1 2pz1 Due to smaller size of F nuclear charge increases. CBSE and NCERT students can refer to the attached file. If the coordinates of a point are (0, -4), then […] Since the valence shell contains = 6 electrons, group No = 10 + 6 = 16 configuration =1s2 2s2 2p6 3s2 3p4  element name is sulphur. Answer:  s-block elements: General electronic configuration: Which important property did Mendeleev use to classify the elements in this periodic table and did he stick to that? Answer:  (a)  All of them are isoelectronic in nature and have 10 electrons each. Therefore, the force that binds the electrons with the nucleus decreases. Which of the following statements related to the modem periodic table is incorrect? Which of the following correctly represents 360g of water? MCQ Questions for Class 11 Business Studies Chapter 3 Private, Public and Global Enterprises with Answers September 8, 2020 September 8, 2020 by Laxmi We have compiled NCERT MCQ Questions for Class 11 Business Studies Chapter 3 Private, Public and Global Enterprises with Answers Pdf free download. Therefore, the correct sequence of decreasing non-metallic character is: F > N > C > B > Si, i.e., option (c) is correct. of electron shells increases and thus the atomic size increases. In this page find links for free mcq questions for class 9 science. Question 29. p-block —ns2 np1- 6 Question 35. For noble gases have positive electron gain enthalpy because energy has to be supplied to the element. (a) K+ (aq) < Na+ (aq) < Li+ (aq) (b) K+ (aq) > Na+ (aq) > Zn2+ (aq) Would you expect the second electron gain enthalpy of O as positive, more negative or less negative than the first? Here You Can Attempt Punjab Chemistry Online Test 11th Class Model Paper Chapter No 3 MCQ's and Short Question Answers online and check grade for higher marks in annual exams. (ii) The electronic configuration of What are Dobereiner’s triads? Thus the atomic radii of the element increases. Answer: (i) Ca (ii) S. Question 9. What are its units? CBSE Class 11 Chemistry Chemical Bonding MCQs. Answer: Nitrogen has exactly half filled p-orbitals. Those which form complex compounds. (iv) f-Block elements: (n – 2) f0-14 (n -1) d0-1 ns2where n = 6 – 7. gives CT ion which does not have stable inert gas configuration, consequently, the energy released is much higher in going from Answer:  Dobereiner arranged certain elements with similar properties in groups of three in such a way that the atomic mass of the middle element was nearly the same as the average atomic masses of the first and third elements. They are generally heavy metals having high melting and boiling points. Question 26. MCQ Questions for Class 11 Business Studies Chapter 3 Private, Public and Global Enterprises with Answers September 8, 2020 September 8, 2020 by Laxmi We have compiled NCERT MCQ Questions for Class 11 Business Studies Chapter 3 Private, Public and Global Enterprises with Answers Pdf free download. NCERT Solutions Class 11 Business Studies, NCERT Solutions Class 11 Entrepreneurship, NCERT Solutions Class 11 Indian Economic Development, NCERT Solutions Class 11 Computer Science, NCERT Solutions for Class 10 Science Chapter 1, NCERT Solutions for Class 10 Science Chapter 2, Periodic Classification of Elements Class 10, NCERT Solutions for Class 10 Science Chapter 7, NCERT Solutions for Class 10 Science Chapter 8, NCERT Solutions for Class 10 Science Chapter 9, NCERT Solutions for Class 10 Science Chapter 10, NCERT Solutions for Class 10 Science Chapter 11, NCERT Solutions for Class 10 Science Chapter 12, NCERT Solutions for Class 10 Science Chapter 13, NCERT Solutions for Class 10 Science Chapter 14, NCERT Solutions for Class 10 Science Chapter 15, NCERT Solutions for Class 10 Science Chapter 16, CBSE Previous Year Question Papers Class 12, CBSE Previous Year Question Papers Class 10, Classification of Elements and Periodicity in Properties, Modern Periodic Law and the present form of the Periodic Table, Nomenclature of Elements with Atomic Numbers > 100, Electronic Configurations of Elements and the Periodic Table, Electronic Configurations and Types of Elements: s-, p-, d-, f – Blocks, Periodic Trends in Properties of Elements. Answer:  Electronic configuration of Na and Mg are In Ga there is 10 3d electrons which do not screen as is done by S and P electrons. Question 2. Deviation of real gases is more at high pressure and low temperature, why? N3-, O2-, F–, Na+, Mg2+, Al3+ Since the last electron has been filled in 4s sub-shell (or orbital), the element belongs to s-block. Their compounds are generally coloured. (c) Aluminium and iodine(d) Silicon and oxygen Question 6. But it is not correct to say that the electronegativity of nitrogen in all the compounds is 3. Answer: Electronic configuration of A (Z = 12) (ii)Seaborg’s group? The first electron gain enthalpy of oxygen is negative because energy is released when a gaseous atom accepts an electron to form monovalent anion. Answer: Electron gain enthalpy of Cl is more negative than that of F. Question 7. Free PDF download of Important Questions for CBSE Class 11 Chemistry Chapter 3 - Classification of Elements and Periodicity in Properties prepared by expert Chemistry teachers from latest edition of CBSE(NCERT) books. Question 16. (e) All of the above Question 24. The higher stability of the completely filled noble gas configuration leads to very high second ionisation enthalpy for sodium. (i) 2 moles of water. Answer: The cause of periodicity in properties is the repetition of similar outer electronic configuration after certain regular intervals. N7 = 1s2 2s2 2px1 2py1 2pz1 (a) gains an electron (b) loses an electron ? How does it vary along a period and along a group? He did stick to it and classify elements into groups and periods. We have provided Classification of Elements and Periodicity in Properties Class 11 Chemistry MCQs … Considering the elements B, C, N, F and Si, the correct order of their non-metallic character is: (a) B>C>Si>N>F (b) Si>C>B>N>F (c) F>N>C>B>Si (d) F>N>C>Si>B Each chapter is divided into smaller quizzes or tests so that it is easy for you at attempt a test. After the loss of first electron, Na+ formed has the electronic configuration of neon (2, 8). Answer:  Isoelectronic species are those species (atoms/ions) which have same number of Free PDF Download - Best collection of CBSE topper Notes, Important Questions, Sample papers and NCERT Solutions for CBSE Class 9 Chemistry Atoms and Molecules. F~ ion has inert gas configuration, While the gain of one electron by MCQ Questions for Class 11 Business Studies with Answers were prepared according to the latest question paper pattern. On the other hand, Ma+ formed after losing first electron still has one more electron in its outermost (3s) orbital. The Ionic radii can be estimated by measuring the distances between cations and anions in ionic crystals. What are the advantages of long . What is screening or shielding effect? It depends upon its state of hybridisation in a particular compound, greater the percentage of s-character, more will be the electronegativity of the element. Question 5. Answer: Question 1. What do you understand by isoelectronic species? Discuss the factors that influence the magnitude of ionization enthalpy. Electron gain enthalpy is denoted by the sign∆egH. Explain why Question 8. Atomic mass of Br =127 + 35.5/2 = 81.25. Which of the above elements is likely to be: The element is Lutenium (Lu). As we move from O to F the atomic size decreases. Chemistry Chapters MCQs Test Class 11: Chemistry is the main subject of the science group at the intermediate level of education. (i) F–(ii) Ar (iii) Mg2+(iv) Rb+ The highest ionization energy is exhibited by (a)atomic number (b) mass number (c) principal quantum number (d) azimuthal quantum number? How do atomic radius vary in a period and in a group? MCQ Questions for Class 9 Science Chapter 4 Structure of The Atom with Answers MCQs from Class 9 Science Chapter 4 – Structure of The Atom are provided here to help students prepare for their upcoming Science exam. Question 1. Register online for Chemistry tuition on … Define electron gain enthalpy. Question 2. All Intermediate 11th Class Students of All Punjab Board can Prepare their Chemistry Book Online by These MCQ Type Test here. Check the below NCERT MCQ Questions for Class 12 Chemistry Chapter 3 Electrochemistry with Answers Pdf free download. Answer: Question 25. A cation is smaller than its parent atom because it has fomer electrons while its nuclear charge remains the same. Name different blocks of elements in the periodic table. Question 8. The values of  ∆ i H1, ∆ iH2  and ∆egH match that of K (potassium). On Pauling scale, the electronegativity of nitrogen, (3.0) indicates that it is sufficiently electronegative. Answer: Within a period, the oxidising character increases from left to right. How do you explain the variation? After the loss of first electron, the electronic configuration of Sudden expansion of gases is called joule Thomson effect? Means element belongs to 4th period belongs to group 4 as in the valence shell (2 + 2) = 4 electrons. Na = 1s2 2s2 2p6 3s1 Where n refer to the number of outermost principal shell. Chemistry XI Notes for 1st Year, Mcqs, Online Mcqs, Theory & Numerical, Questions Answers, Fill In The Blanks for All Chapters - Class XI, 11th, 1st Year Chapter # 01 Introduction To Fundamental Concepts Of Chemistry (c) electron-electron interaction in the outer orbitals O (g) + e– —> O– (g) (∆ eg H = – 141 kJ mol -1) Mg+ = 1s2 2s2 2p6 3s1 Those students who want to get good marks in the papers, try to solve all the MCQs, short question answer, fill in the blanks, Multiple choice, and get the results instantly. Question 38. Energy of an electron in the ground state of the hydrogen atom is- 2.18 x 10-18 J.Calculate the ionization enthalpy of atomic hydrogen in terms of JMol-1. State the Modem Periodic Law. Chemistry MCQs for Class 11 Chapter Wise with Answers PDF Free Download is very important for students who want to score good marks in their CBSE board examination. They are generally paramagnetic in nature. They generally form electropositive ion by losing 1 or 2 electrons, that’s why they are electro positive in nature. Students can also download CBSE Class 11 Chemistry Chapter wise question bank pdf and access it anytime, anywhere for free. The process may be represented by MCQ Questions for Class 11 Chemistry with Answers were prepared based on the latest exam pattern. Discuss the main characteristics of four blocks of elements in the periodic table? Loss of an electron from an atom results in the formation of a cation. (a) Bond length (b) Electronegativity These FSc part 1 biology notes include detailed MCQs notes of Chapter 3 Enzymes. This has made the study simple because the properties of elements are now studied in form of groups rather than individually. Question 7. s-block —ns1-2 Chapter 4. Question 13. Reason. The first ionization enthalpy values (in kJ mol -1) of group 13 elements are: The values of  ∆ i H1, ∆ iH2 and ∆egH match that of F (fluorine). What are inner transition metals? Question 36. 10 min. If you want to practice more MCQs… (b) Identify the element that would tend to lose two electrons. O– (g) + e– —> O 2- (g) (∆ eg H = + 780 kJ mol -1) (a) B (b) N (c) Al (d) P . Question 9. Contents. (c) Each block contains a number of columns equal to the number of electrons that can occupy that subshell. (a) AgOH (b) PbI4 (c) PI5 (d) SH6 Since the ionization enthalpy decreases down the group therefore, the reactivity of group 1 elements increases in the same order Li < Na < K < Rb < Cs. Unit of electron gain enthalpy is kJ/ mol. have same No. It is linked with electron gain enthalpy and electronegativity. Question 5. Question 4. MCQ Questions for Class 12 Chemistry with Answers were prepared based on the latest exam pattern. Chemistry Chapter 11 is the most important subject of Science students of 10th class. Answer: (i) n = 3 Consequently, At of Be is higher than that  ∆iH1 of B. The atoms in the gaseous state are far separated in the sense that they do not have any mutual attractive and repulsive interactions. Prepare from hundreds of questions for Chapter 3 chemistry 11th class. (a) Sn02 (b) CO (c) Al203 (d) Na20 The elements in the same group have similar properties due to their outer-most (valence shell) configuration. Question 3. First electron in both cases has to be removed from 3s-orbital but the nuclear charge of Na (+ 11) is lower than that of Mg (+ 12) therefore first ionization energy of sodium is lower than that of magnesium. value from B to Al is due to the bigger size of Al. Considering the elements B, Al, Mg and K, the correct order of their metallic character is:(a) B> Al> Mg > K(b) Al> Mg > B> K (c) Mg > Al> K> B (d) K> Mg > Al> B What is the relationship between volume and temperature at constant pressure for a given mass of a gas? Question 8. Therefore, the period indicates the value of principal quantum number. A solid has a definite shape and volume. Answer: A cation is smaller than the parent atom because it has fewer electrons while its nuclear Among the second period elements, the actual ionization enthalpies are in the order: Li M+ (g) + e–(g) (b) 1.806 × … In contrast,Cl207 reacts with water to form perchloric acid which turns blue litmus red. With NEET Chemistry MCQs section students can delve into hundreds of questions appearing in the previous years and also gauge the importance of topics. F ->F– From left to right across a period atomic radii generally decreases due Answer: In a multielectron atom, the electrons present in the inner shells shield the electrons in the valence shell from the attraction of the nucleus or they act as a screen between the nucleus and these electrons. Students can practice the NCERT MCQ Questions for Class 10 Science Chapter 3 Metals and Non-Metals with Answers Pdf free download is available here. Now that you are provided all the necessary information regarding CBSE Class 11 Chemistry Worksheet and we hope this detailed article is helpful. ‘. Therefore, there is an unexpected increase in the magnitude of effective nuclear charge resulting in increased ∆iH1 values. It makes the study of elements systematic and simple. Answer: (a) Variation of atomic radius in a group: Which of the following statements is incorrect in relation to ionization enthalpy? The reason for the deviation is due to the smaller size of F. Due to its small size, the electron repulsions in the relatively compact 2p-subshell are comparatively large and hence the attraction for incoming electron is less as in the case of Cl. MCQs With Answers. What is the basic difference in approach between Mendeleev’s Periodic Law and the Modem Periodic Law? Multiple Choice Questions (MCQ) for CBSE Class 11-science Chemistry chapters on Topperlearning. Answer: It is the energy required to remove an electron from an isolated gaseous atom in its ground state. Answer: Question 15. Question 4. Variation within a group. (a) 1.806 × 1023. The orbitals present in this shell are 6s, 4f, 5p, and 6d. (c) Element belonging to oxygen family (group 16) e.g., oxygen. Elements A, B, C and D Iwoe atomic numbers 12,19, 29, and 36 respectively. It is compulsory for those who choose the science group. (d) The block indicates value of azimuthal quantum number (l)for the last subshell that received electrons in building up the electronic configuration. Question 19. Chemistry Topics Wise MCQs. Question 7. Class 10; Chemistry; MCQ; CBSE Class 10, Chemistry, MCQ. These MCQ's are extremely critical for all CBSE students to score better marks. Thus, overall decreasing order of oxidising power is: F > O > Cl > N, i.e., option (b) is correct. (i)Lawrence Berkeley Laboratory (d) Number of core electrons. Question 28. Na —> Na++ e– The entire NCERT textbook questions have been solved by best teachers for you. https://byjus.com/chemistry/important-questions-class-11-chemistry Answer: Ionization Enthalpy. Solving the Objective Questions for 12th Class Chemistry helps you be aware of the type of the questions asked in the exam. Question 1. For these reasons, the energy required to remove an electron from magnesium is more than the energy required in sodium. Cl207 +H20——–>2HClO4 (i) O or F (ii) F or Cl. (ii) p-Block elements: ns2 np1-6 where n = 2-6. (c)End of valence electrons is marked by a big jump in ionization enthalpy. Give four examples of species which are isoelectronic with ca2+. Answer: The element is chlorine (Cl) with atomic number (Z) = 17. Revise all the concepts easily by taking help from the MCQ Questions for Class 10 Science with Answers are prepared based on the latest exam pattern. Ionic radius. B        Al       Ga       In      Tl Atomic mass of Na =(39+7)/2= 23 On moving down the group their reactivity increases. Separate sections for each chapter students will find. Download MCQs for Class 11 Chemistry for important topics for all chapters in Class 11 Chemistry based on CBSE and NCERT pattern. Each topic has hundreds of Chemistry questions and answers multiple choice. When the liquid is spun rapidly, the denser particles are forced to the bottom and the lighter particles stay at the top. General electronic configuration of s-block elements: ns1 – 2 where n = 2 – 7 Question 3. What is the cause of periodicity in properties of the elements? The increasing order of reactivity among group 1 elements is Li < Na < K < Rb < Cs whereas that of group 17 is F > Cl > Br > I. How would you react to the statement that the electronegativity ofN on Pauling scale is 3.0 in all the nitrogen compounds? Question 29. (a) Phosphorous (b) Oxygen (c) Sulphur (d) Nitrogen Since the metal forms a predominarly stable covalent halide of the formula MX (X = halogen), therefore, the alkali metal must be least reactive. (a) F > Cl> O > N (b) F > O > Cl> N (c) Cl> F > O > N (d) O > F > N > Cl Write the atomic number of the element present in the third period and seventeenth group of the periodic table. In that case energy has to be supplied. Question 12. Contents. Check the below NCERT MCQ Questions for Class 11 Chemistry Chapter 9 Hydrogen with Answers Pdf free download. Each chapter is divided into smaller quizzes or tests so that it is easy for you at attempt a test. Thus the radius of Na+will be less than the Na. It means electrons in a particular atom are in the lowest energy state and they neither lose nor gain electron. This also increases, the effective nuclear charge thus the value of ∆iH1 increases. Answer: (c) Nuclear mass. Answer: Lanthanoids (the fourteen elements after Lanthanum) and actinides (the fourteen elements after actinium) are called inner transition elements. Class 11 Biology Syllabus (2017-18) The Living World (NCERT Chapter Solutions) The Living World (AIPMT 7 MCQs) The Living World (Taxonomical Aids) The Living World VSQA An overview of Virus and Viroids (Q & A) Biological Classification (NCERT Chapter Q & A) Scientific Names Kingdom Fungi (AIPMT MCQs) Plant Nutrition MCQs (AIPMT/NEET) The same is with into Tl. The electronic configuration of an element is Is 2s 2p 3s 3p 4s . Answer: The elements of s and p-block are collectively called representative or main group elements. Answer: Within a group Atomic radius increases down the group. As a result, the second ionisation enthalpy of magnesium is much smaller than that of sodium. Last electron goes to the f-orbital, element is from f-block. Thus, C is more non-metallic than Si. Click on the respective chapter or topic to get MCQs of respective chapter. The type of questions that will be asked from NCERT Class 11 Chemistry Chapter 3 are displayed in the below provided NCERT Exemplar Class 11 Chemistry Chapter 3. Sod.oxide                Sod.hydroxide Therefore, metallic character of K, Mg and Al decreases in the order: K > Mg > Al. Multiple Choice Questions (MCQ) for CBSE Class 11-science all subjects on Topperlearning. = 1.312 x 106 J mol-1. What does atomic radius and ionic radius really mean to you? CBSE Board has brought a major modification in the Exam Pattern and plans to introduce more MCQ Questions with Answers in the Board Exams. Question 9. Thus, F is a stronger oxidising agent than Cl. Answer: Ar, K+, CT, S2-, or P3- are isoelectronic with ca2+. 6. Answer: (i) s-Block elements: ns 1-2 where n = 2 – 7. Question 10. Atomic mass: 35.5    80             127 Give reasons: (b) (i) Radius of cation is less than that of the atom: For example, View Top Scorers. CBSE Class 11th Chemistry Chapter 3 NCERT solutions are the best material that students can get to study better and lessen some stress that they might face during the hectic year ahead. Question 5. (iii) In iso-electronic ion, the ionic radii decreases with increase in atomic number. Answer: 1. Atomic mass: 7          23              39 Answer: (i) O or F. Both O and F lie in 2nd period. However, within a group, the metallic character, increases from top to bottom. Now that you are provided all the necessary information regarding CBSE Class 11 Chemistry Worksheet and we hope this detailed article is helpful. Give their general electronic configuration. Thus, among B, C, N and F, non-metallic character decreases in the order: F > N > C > B. Gas fills the entire volume of a container. The tendency to lose electrons in turn, depends upon the ionization enthalpy. The size of anion will be larger than that of parent atom (c) The ionization energy of the element (d) Oxidizing power Question 31. We can see that in case of nitrogen 2p-orbitals are exactly half filled. NCERT Class 11 Chemistry Chapter 3 is for Classification of Elements and Periodicity in Properties. Free NCERT Solutions for Class 11 Chemistry Chapter 3 Classification of Elements and Periodicity in Properties solved by expert teachers from latest edition books and as per NCERT (CBSE) guidelines.Class 11 Chemistry Classification of Elements and Periodicity in Properties NCERT Solutions and Extra Questions with Solutions to help you to revise complete Syllabus … (ii) Radius of anion is more than that of the atom. (b) Nuclear charge (Z) Question 21. What are the various factors due to which the ionization enthalpy of the main group elements tends to decrease down the group? Answer: The sixth period corresponds to sixth shell. FSC students with pre-medical and pre-engineering studies are asked to study chemistry subjects. (ii) Noble gases have positive value of electron gain enthalpy. (a) ns2 np4 (b) ns2 np6 (c) ns2 np2 (d) ns2 =1s2 2s2 2p6 3s2 3p6 3d10 4s1 n – 4, period = 4 Block = d Electronic configuration of D (Z = 36) (c) Identify the element that would tend to gain two electrons. Explain why chlorine can be converted into chloride ion more easily as compared to fluoride ion from fluorine ? Assign the position of the element having outer electronic configuration,

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